Answer:
Velocity = 20.3 [m/s]
Step-by-step explanation:
This is a typical problem of energy conservation, where potential energy is converted to kinetic energy. We must first find the potential energy. In this way, we will choose as a reference point or point where the potential energy is zero when the carrriage rolls down 21 [m] from the top of the hill.
![E_(p) =m*g*h\\ where:\\m = mass = 25[kg]\\g = gravity = 9.81 [m/s^2]\\h = elevation = 21 [m]\\E_(p) =potential energy [J]\\E_(p) =25*9.81*21=5150[J]](https://img.qammunity.org/2021/formulas/physics/middle-school/8juwm6s3jh2jcgim14cu1kxqst4mqtukf6.png)
Now this will be the same energy transformed into kinetic energy, therefore:
![E_(p)=E_(k) = 5150[J]\\E_(k) =0.5*m*v^(2) \\where:\\v=velocity [m/s]\\v=\sqrt{(E_(k))/(0.5*25) } \\v=20.3[m/s]](https://img.qammunity.org/2021/formulas/physics/middle-school/d8fv74ck7jkvjhrnjynojg1mxv8ok2o7g9.png)