Question

3 C2H2(g) → C6H6(g) What is the standard enthalphy change ΔHo, for the reaction represented above? (ΔHof of C2H2(g) is 230 kJ mol-1; (ΔHof of C6H6(g) is 83 kJ mol-1;)

Answer 1

Answer: The standard enthalpy change is -607kJ

Step-by-step explanation:

The given balanced chemical reaction is,

`3C_2H_2(g)\rightarrow C_6H_6(g)`

First we have to calculate the enthalpy of reaction
`(\Delta H^o)`.

`\Delta H^o=H_f_(product)-H_f_(reactant)`

`\Delta H^o=[n_(C_6H_6)* \Delta H_f^0_((C_6H_6))]-[n_{C_2H_2* \Delta H_f^0_((C_2H_2))]`

where,

We are given:

`\Delta H^o_f_((C_2H_2))=230kJ/mol\\\Delta H^o_f_((C_6H_6))=83kJ/mol`

Putting values in above equation, we get:

`\Delta H^o_(rxn)=[(1* 83)]-[(3* 230)]=-607kJ`

The standard enthalpy change is -607kJ