Question

Help math homework both questions

Answer 1

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

Now, According to figure

Sin angle =
`(\textrm perpendicular)/(\textrm hypotenuse)`

Or, Sin Ф =
`(\textrm x)/(\textrm e)`

Or, Sin 45° =
`(\textrm x meters)/(\textrm 1.2 meters)`

Or, 0.707 × 1.2 meters = x

∴ x = 0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters . Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend = Ф = 22°

Let the glide runway path = y feet

Now, According to question

Tan angle =
`(\textrm perpendicular)/(\textrm base)`

Or, Tan Ф =
`(\textrm H)/(\textrm y)`

Or, Tan 22° =
`(\textrm  10,000 feet)/(\textrm y feet)`

Or, 0.4040 =
`(\textrm  10,000 feet)/(\textrm y feet)`

Or, y =
`(\textrm  10,000 feet)/(\textrm 0.4040)`

∴ y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer