Question

Buses to Shenley leave the bus station every 40 minutes.

Buses to Winley leave every 15 minutes.
At 8.15 a.m. buses to both Shenley and Winley leave the bus station. When is the next time that buses to both places leave at the same time?

Answer 1

The next time that buses to both Shenley and Winley leave at the same time is 10:15 a.m., two hours after 8:15 a.m.

Step-by-step explanation:

To find the next time that buses to both Shenley and Winley leave at the same time, we need to determine the least common multiple (LCM) of 40 minutes and 15 minutes. The LCM is the smallest number that is divisible by both 40 and 15.

The LCM of 40 and 15 is 120. Therefore, buses to both Shenley and Winley will leave at the same time after 120 minutes, which is equivalent to 2 hours.

So, the next time that buses to both Shenley and Winley leave at the same time is 10:15 a.m., two hours after 8:15 a.m.

Answer 2

So first and foremost you look for the lcm, least common multiple of 40 and 15 minutes.

• the lcm is 120 minutes
• convert 120 minutes into hours so which is equals to 2 hours
• after converting into hours you say it 15 a.m. plus 2 hours which is equals to 10:15 a.m.
• so your answer is 10:15 a.m. you're welcome