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The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.

User Akaphenom
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1 Answer

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Answer:


A\approx 28^(\circ)

Explanation:

Please find the attachment.

We have been given that area of triangle ABC is 3√2 square inches.


\text{Area}=(1)/(2)\text{Base}* \text{height}

We know that area of triangle an be found using trigonometry as:


\text{Area}=(1)/(2)* c* h


\text{sin}(A)=(h)/(9)\\h=9\cdot \text{sin}(A)


3√(2)=(1)/(2)* 2* 9\cdot \text{sin}(A)


3√(2)=9\cdot \text{sin}(A)


9\cdot \text{sin}(A)=3√(2)


\text{sin}(A)=(3√(2))/(9)


\text{sin}(A)=(√(2))/(3)

Now, we will use inverse sine to find the value of angle A as:


A=\text{sin}^(-1)((√(2))/(3))


A=28.1255057^(\circ)


A\approx 28^(\circ)

Therefore, the measure of angle A is approximately 28 degrees.

The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle-example-1
User Joe Heffer
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