Question

A car came to a stop from a speed of 28 m/s in a time of 2.1 seconds. What

was the acceleration of the car?

Answer 1

The answer is : -13.3 m/s^2

Answer 2

Answer:
`-13.33 m/s^(2)`

Explanation:

We can solve this problem with the following equation:

`a=(V-V_(o))/(\Delta t)`

Where:

`a` is the acceleration of the car

`V_(o)=28 m/s` is the initial velocity of the car

`V=0 m/s` is the final velocity of the car

`\Delta t=2.1 s` Is the time in which the car came to a stop

Solving:

`a=(0 m/s - 28 m/s)/(2.1 s)`

`a=-13.33 m/s^(2)` This is the car's acceleration, note the negative sign indicates the car was decreasing its velocity before coming to a stop.