140k views
2 votes
What is the area of the figure?

40 ft2
84 ft2
96 ft2
can't be determined

What is the area of the figure? 40 ft2 84 ft2 96 ft2 can't be determined-example-1
User Nausik
by
3.3k points

2 Answers

3 votes

Answer:

80ft^2

Explanation:

User Christoph Glur
by
3.5k points
3 votes

Answer:


A=80\ ft^2

Explanation:

we know that

The area of the figure is equal to the area of an isosceles triangle (has two equal sides) plus the area of a rectangle

step 1

Find the area of the triangle

The area of the triangle is equal to


A=(1)/(2)bh

we have


b=16\ ft

To find out the height of the triangle Apply the Pythagorean Theorem


10^2=(16/2)^2+h^2

solve for h


100=64+h^2


h^2=100-64


h^2=36


h=6\ ft

Find the area of triangle


A=(1)/(2)(16)(6)


A=48\ ft^2

step 2

Find the area of rectangle

The area of rectangle is equal to


A=LW

we have


L=16\ ft\\W=2\ ft

substitute


A=(16)(2)=32\ ft^2

step 3

Find the area of the figure

Adds the areas


A=48+32=80\ ft^2

User Dewalla
by
2.9k points