Question

An ideal heat engine absorbs heat at 100°C and exhausts heat at 0°C. What is its percent efficiency?

Answer 1

26.8 %

Step-by-step explanation:

TH = 100°C = 100 + 273 = 373 K

Tc = 0°C = 273 K

The efficiency of the heat engine is given by

`\eta = 1-(T_(c))/(T_(H))`

`\eta = 1-(273)/(373)`

η = 0.268

η = 26.8 %

Thus, the efficiency of the heat engine is 26.8 %.