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100 points - please help - chemistry

Question 1:
Ion charges: (Na^+, Cu^2+, OH^-,
NO_(3-)
Write a balanced chemical equation for the change you observed in the laboratory
Answer:
Note that the reaction in this experiment is:
Copper (II) nitrate + sodium hydroxide → copper (II) hydroxide +sodium nitrate

Question 2:
Ion charges: (Na^+, Fe^2+, OH^-, SO4^2-)
Write a balanced chemical equation for the change you observed in the laboratory
Answer:
Note that the reaction in this experiment is:
Iron (II) sulfate + sodium hydroxide → iron (II) hydroxide + sodium sulfate

Question 3:
Ion charges: (Na^+, Fe^3+, OH^-, NO3^-)
Write a balanced chemical equation for the change you observed in the laboratory
Answer:
Note that the reaction in this experiment is;
Iron (III) nitrate + sodium hydroxide → iron (III) hydroxide + sodium nitrate
How many grams of sodium nitrate formed when 1.5 moles of iron (III) nitrate reacted with excess of sodium hydroxide? Note: use a periodic table, write units for your result and SHOW YOUR WORK ☺

User PopKernel
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1 Answer

7 votes

Answer:

Step-by-step explanation:

1. Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3

2. FeSO4 + 2 NaOH = Fe(OH)2 + Na2SO4

3. Fe(NO3)3 + 3 NaOH = Fe(OH)3 + 3 NaNO3

For the second part of 3 since it tells us NaOH is excess we dont care about it. We use our balanced equation 3 to get the correct molar ratios to solve this.

1.5mol Fe(NO3)3 x 3mol NaNO3/1mol Fe(NO3)3 x 84.99gNaNO3/1molNaNO3

= 382.455g NaNO3

User Tom Blodget
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3.8k points