Question

What is the surface area of the rectangular pyramid below?

A rectangular pyramid. The rectangular base has a length of 4.8 meters and height of 3.8 meters. 2 triangular sides have a base of 4.8 meters and height of 2.6 meters. 2 triangular sides have a base of 3.8 meters and height of 2.9 meters.

Answer 1

Step-by-step explanation:The area of the base is 24 cm2.

There are four lateral faces.

The total surface area of the figure is 66.4 cm2.

i just did the test

Answer 2

`SA=41.74\ m^2`

Explanation:

we know that

The surface area of the rectangular pyramid is equal to the area of its rectangular base plus the area of its four triangular faces

so

step 1

Find the area of its rectangular base

`A=(4.8)(3.8)`

`A=18.24\ m^2`

step 2

Find the area of its four triangular faces

`A=2[(1)/(2)(4.8)(2.6)]+2[(1)/(2)(3.8)(2.9)]`

`A=12.48+11.02=23.5\ m^2`

step 3

Find the surface area

Adds the areas

`SA=18.24+23.5`

`SA=41.74\ m^2`