Question

How many moles are in 1.58*10^24 atoms of zinc?

Answer 1

2.6 moles are present in the given number of atoms of zinc.

Step-by-step explanation:

It is known that 1 mole of any element contains Avagadro's number of atoms. So

`1 mole of Zn = 6.022*10^(23) atoms`

Then,

`1 atom of Zn = (1)/(6.022*10^(23) )` moles

As here it is given that there is 1.58 *
`10^(24)` atoms of Zinc, then the number of moles in these number of atoms will be

`No. of moles in 1.58 *10^(24) atoms of Zn = (1.58*10^(24) )/(6.022*10^(23) )` moles

`No. of moles = 2.6 moles`

Hence, there are 2.6 moles in 1.58 * 10^24 atoms of zinc