Question

4Fe + 3o2 - 2Fe2o3 When iron rusts in air, iron (III) oxide is produced. How many moles of oxygen react with 2.4 moles of iron in the rusting process?

Answer 1

moles of oxygen (O₂) = 1.8 mole

Step-by-step explanation:

Data Given:

moles of Fe (iron) = 2.4 moles

moles of Oxygen (O₂) = ?

Reaction Given

4Fe + 3O₂ --------> 2Fe₂O₃

Solution:

To solve this problem we have to look at the reaction

Reaction Given

4Fe + 3O₂ ----------> 2Fe₂O₃

4 mol 3 mol

So if we look at the reaction; 4 mole of iron (Fe) react with 3 moles of oxygen (O₂) in a rusting reaction, then how many moles of oxygen (O₂) will react with 2.4 moles of iron (Fe)

For this apply unity formula

4 mole of iron (Fe) ≅ 3 moles of oxygen (O₂)

2.4 mole of iron (Fe) ≅ X moles of oxygen (O₂)

By Doing cross multiplication

moles of oxygen (O₂) = 3 moles x 2.4 moles / 4 mole

moles of oxygen (O₂) = 1.8 mol

2.4 mole of iron (Fe) will react with 1.8 moles of oxygen (O₂)