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These tables represent a quadratic function with a vertex at (0,3). What is the average rate of change for the interval from X =9 to x= 10?

2 Answers

3 votes

Answer:

-19

Explanation:

User Georgy Nemtsov
by
4.6k points
3 votes

Answer:

-19

Explanation:

The missing table is shown in the attachment.

Since the quadratic function has vertex at (0,3), its equation is of the form;


y = a {x}^(2) + 3

To find the value of 'a' we substitute any other point from the table say (1,2) to get:


2 = a( {1)}^(2) + 3


a = 2 - 3 = - 1

Hence the function is


y = - {x}^(2) + 3

Now


f(10) = - 100 + 3 = - 97


f(9) = - 81 + 3 = - 78

The average rate of change from x=9 to x=10 is


(f(10) - f(9))/(10 - 9) = ( - 97 - - 78)/(1) = - 19

These tables represent a quadratic function with a vertex at (0,3). What is the average-example-1
User JuanSedano
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