Question

(1) What is the distance between the points (–8, –2) and (–7, –2)?

A 1
B6
C10
D15


(2) What is the perimeter of rectangle ABCD shown on the coordinate plane?



5 units



6 units



8 units



10 units

Answer 1

The distance between points (- 8 , - 2) , ( - 7 , - 2) is 1 unit

Explanation:

Given as :

The coordinate are

`x_1` ,
`y_1` = - 8 , - 2

`x_2` ,
`y_2` = - 7 , - 2

Let The distance between the points = d

So, d =
`\sqrt{(x_2 - x_1)^(2) + (y_2 - y_1)^(2) }`

Or, d =
`\sqrt{((-7) - (-8))^(2) + ((-2) - (-2))^(2) }`

Or, d =
`\sqrt{(-7 + 8)^(2) + (- 2 + 2)^(2) }`

Or, d =
`\sqrt{(1)^(2) + (0)^(2) }`

Or, d =
`√(1 + 0)`

∴ d =
`√(1)`

i.e d = 1

So, The distance between the points = d = 1 unit

Hence, The distance between points (- 8 , - 2) , ( - 7 , - 2) is 1 unit Answer