Question

8 The combustion of sulfur leads to the forma

tion of only one product, sulfur dioxide. We
burn 1.6g of sulfur in air.
a) Write the equation of the reaction.
b) Calculate the mass of the product
formed.
​

Answer 1

a) S + O₂ -------> SO₂

b) 3.2 g of SO₂

Step-by-step explanation:

Data Given:

combustion of sulfur in air

Amount of sulfur = 1.6 g

1. equation of the reaction = ?

2. mass of product = ?

Solution:

Combustion of Sulfur:

It is a burning process of sulfur in air. In this reaction sulfur react with oxygen and give sulfur dioxide.

Balance reaction for this is as under

S + O₂ -------> SO₂

Now to find mass of the product

For this first look at the reaction

S + O₂ -------> SO₂

1 mol 1 mol

Convert moles to mass

Molar mas of S = 32 g/mol

Molar mas of SO₂ = 32 + 2(16)

Molar mas of SO₂ = 32 + 32 = 64 g/mol

So,

S + O₂ -----------> SO₂

1 mol(32 g/mol) 1 mol (64 g/mol)

32 g 64 g

As from the above calculation it is clear that 32g of sulfur (S) gives 64 g of (product) SO₂; then how many gram of product will produces from 1.6g of sulfur.

Appy unity Formula

32 g of S = 64 g of SO₂

1.6 g of S = X grams of SO₂

Do cross multiplication

mass of SO₂ = 64 g x 1.6 g / 32 g

mass of SO₂ = 3.2 g of SO₂

So mass of product (SO₂) = 3.2 g