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Find (ƒ • g)(x) where ƒ(x) = x2 + 2, g(x) = x – 3.

User Raptor
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\text{The value of } (f.g)(x) \text{ is }(f * g)(x) =x^3-3x^2+2x-6

Solution:

Given that:


f(x) = x^2+2


g(x) = x - 3

We have to find (f . g)(x)

The formula for (f . g)(x) is given as:


(f * g)(x) = (f (x))(g(x))

Substitute the given functions f(x) and g(x)


(f * g)(x) =(x^2+2)(x-3)

Multiply both functions

Multiply each term in first bracket with each terms in second bracket


(f * g)(x) = (x^2)(x)-3(x^2)+2(x) + 2(-3)\\\\(f * g)(x) =x^3-3x^2+2x-6

Thus the value of (f .g)(x) is found

User Akahunahi
by
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