Final answer:
The two roots of the polynomial 4x^2 - 6x + 1 are found using the quadratic formula, providing the approximate values of 1.306 and 0.191.
Step-by-step explanation:
The roots of the polynomial 4x^2 - 6x + 1 can be found using the quadratic formula, which is x = (-b ± √(b^2 - 4ac)) / (2a) for any quadratic equation of the form ax^2 + bx + c = 0. In this case, a = 4, b = -6, and c = 1.
Plugging these values into the quadratic formula gives us:
x = (6 ± √((-6)^2 - 4 * 4 * 1)) / (2 * 4)
x = (6 ± √(36 - 16)) / 8
x = (6 ± √20) / 8
Since √20 is approximately 4.472, this gives us two roots:
- x = (6 + 4.472) / 8
- x = (6 - 4.472) / 8
Which simplifies to:
Therefore, the two roots of the polynomial are approximately 1.306 and 0.191.