Answer:
The answer to your questions is below
Explanation:
4.-
In a 45°-45°-90° triangle, the length of the legs are "x" and the length of the hypotenuse is x
![√(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zk4ls2i7rszmygzgqi2kkfexuqtms266jg.png)
Then, in this problem, the length of the leg is 7 then the length of the hypotenuse will be 7
![√(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zk4ls2i7rszmygzgqi2kkfexuqtms266jg.png)
5.- In a 30°-60°-90° triangle, the length of the hypotenuse is 2x, the length of the longer leg is x
and the length of the shorter leg is x.
In this problem we have the length of the hypotenuse = 20 and find x.
2x = 20
x = 20/2
x = 10
longer leg = x
![x√(3) =<strong> 10√(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3uvdz1ayyxogpfsqdx94zwy2iw2g6wpk37.png)
6.- nonzero
7.- hypotenuse = 20 cm
Find x
2x = 20
x = 20/2
x = 10
Shoter leg = x = 10 cm