Question

Steve skated 12 kilometers in 52 minutes. Then he turned around and took the same path back to his starting point, arriving 3 hours and 24 minutes later. What was his average speed during his trip?

Answer 1

His average speed was 0.144km/min

Explanation:

At first Steve traveled 12 kilometers for 52 minutes, therefore his speed was

`12km/52min=0.2308km/min`

On his return journey he travels the same distance but in 3 hours 24 minutes or in 204 minutes; therefore his speed during his return journey was

`12km/204min=0.0589km/min`

So his average speed during his trip was just the average of these two speeds:

`S_(avg)=(0.2308+0.0589)/(2) =\boxed{0.1448km/min}`