Question

Find the equation of a line passing through (-3, 3) and parallel to 4x + 3y =3

Answer 1

`4x + 3y = - 3`

Explanation:

The line is parallel to 4x+3y=3.

We rewrite this line in slope intercept form to deduce our slope.

`y = - (4)/(3) x + 3`

The slope is

`m = - (4)/(3)`

The line passes through (-3,3) so we use the point-slope formula:

`y-y_1=m(x-x_1)`

`y - 3 = - (4)/(3) (x - - 3)`

We simplify to get:

`y= - (4)/(3)x - 4 + 3`

`y= - (4)/(3)x - 1`

We rewrite in standard form to get:

`3y = - 4x - 3`

`3y + 4x = - 3`