The midpoint of given points is

The distance between the given points is 8.6023 units
Solution:
Given that two points are (-6, 5) and (-1, -2)
We have to find the midpoint and distance
The midpoint of two given points is given as:

Here in this sum,

Substituting the values in formula, we get

Thus the midpoint of given points is

Distance between given points:
The formula for distance is given as:

Substituting the values in formula, we get

D = 8.6023 units
Thus the distance between the given points is 8.6023 units