Answer: the solutions are (2, 5)
Explanation:
The given system of simultaneous equations is
5x – 4y = -10 - - - - - - - - - - - 1
3x + 2y = 16 - - - - - - - - - - -2
We would eliminate x by multiplying equation 1 by 3 and equation 2 by 5. It becomes
15x - 12y = - 30
15x + 10y = 80
Subtracting, it becomes
- 22y = - 110
Dividing the left hand side and right hand side of the equation by - 22, it becomes
- 22y/-22 = - 110/-22
y = 5
Substituting y = 5 into equation 1, it becomes
5x – 4 × 5 = -10
5x - 20 = - 10
5x = - 10 + 20
5x = 10
x = 10/5 = 2