Question

Please help me solve this answer it all for me please

Answer 1

The slopes are

`m1=(2)/(5), m2=-(5)/(2)`

Therefore, the equations are equations of Perpendicular Lines .

Explanation:

Given:

`y=(2)/(5)* x + 1` ......................Equation ( 1 )

`5x+2y=-4\\\\\therefore y = (-5)/(2)* x-2` ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

`y=mx+c`

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 =
`(2)/(5)`

Step 2.

Slope of equation 1 = m2 =
`-(5)/(2)`

Step 3.

Product of Slopes = m1 × m2 =
`(2)/(5)* -(5)/(2)=-1`

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

The slopes are

`m1=(2)/(5),m2=-(5)/(2)`

Therefore, the equations are equations of Perpendicular Lines .