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19

.
| Pb + 2 HI → _Pbl, + 1_H,
a). How many moles of Pbl, are produced from the reaction of 28 moles of
HI?

1 Answer

4 votes

Answer:

no. of moles of PbI₂ = 14 moles

Step-by-step explanation:

Data Given:

no. of moles of HI = 28 moles

no. of moles of Pbl₂ = ?

Reaction Given

Pb + 2HI -------→ Pbl₂ + H₂

Solution:

To solve this problem we have to look at the reaction

Reaction:

Pb + 2HI -------→ Pbl₂ + H₂

2 mol 1 mol

So if we look at the reaction 2 mole of hydrogen iodide (HI) gives 1 moles of Lead iodide (PbI₂), then how many moles of Lead iodide (PbI₂) will be produced by 28 moles of hydrogen iodide (HI)

For this apply unity formula

2 mole of HI ≅ 1 moles of PbI₂

28 mole of HI ≅ X moles of PbI₂

By Doing cross multiplication

moles of PbI₂ = 28 moles x 1 moles / 2 mole

moles of PbI₂ = 14 mole

28 mole of HI will produce 14 moles of PbI₂

User GreNodge
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