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Evaluate the sum from n equals five to nine of quantity three n plus two

User Lnvrt
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2 Answers

4 votes

Answer:

115

Explanation:

took test

User Nklauza
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5.2k points
4 votes

Answer:

The given expanded sum of the series is
\sum\limits_(n=5)^(9)3n+2=115

Explanation:

Given problem can be written as


\sum\limits_(n=5)^(9)3n+2

To find their sums:

Now expanding the series

That is put n=5,6,7,8,9 in the given summation


\sum\limits_(n=5)^(9)3n+2=[3(5)+2]+[3(6)+2]+[3(7)+2]+[3(8)+2]+[3(9)+2]


=[15+2]+[18+2]+[21+2]+[24+2]+[27+2]


=17+20+23+26+29 (adding the terms)


=115

Therefore
\sum\limits_(n=5)^(9)3n+2=115

Therefore the given sum of the series is
\sum\limits_(n=5)^(9)3n+2=115

The given expanded sum of the series is
\sum\limits_(n=5)^(9)3n+2=115

User Catty
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