Question

"What is the approximate centripetal acceleration of an object (mass = 50 g) on the end of an 80-cm string rotating at a constant rate of 2 times a second?"

Answer 1

Answer:
`a_c=126.36 m/s^2`

Step-by-step explanation:

Given

mass of object
`m=50 gm`

length of string
`L=80 cm`

Angular frequency
`\omega` will be
`(4\pi)/(1)` rad/s because it completing 2 complete circle in 1 sec

In rotation object turned
`2\pi` rad so for 2 rotation it will be
`4\pi`

centripetal acceleration is the inward acceleration experiences by an object when it moves in a circular path and it is given by

`a_c=\omega ^2* L`

`a_c=(4\pi )^2* 0.8`

`a_c=126.36 m/s^2`