Question

Can anyone please explain to me on how to do a math problem like this? It’s solving linear equations by elimination, and I’m very confused. I need it in detail.

Answer 1

(x, y) = (3, -2)

Explanation:

4x + 3y = 6

-x - 3y = 3

Sum the equations vertically to eliminate at least one variable:

3x = 9

Divide both sides of the equation by 3:

x = 3

Substitue the given value of x into the equation -x - 3y = 3:

-3 - 3y = 3

Solve the equation for y:

y = -2

The solution of the system is the ordered pair (x, y):

(3, -2)

Check if the given ordered pair is the solution of the system of equations:

4 x 3 + 3 x (-2) = 6

-3 - 3 x (-2) = 3

Simplify the equalities:

6 = 6

3 = 3

Since all of the equalities are true, the ordered pair is the solution of the system:

(x, y) = (3, -2)

I hope this helped!

Answer 2

Explanation:

In this problem you’d need to multiply 4 on the bottom equation to make -x into -4x and from there the 4x on the top equation and the -4x in the bottom equation cancel out. Don’t forget, if you are multiplying 4 on the bottom equation you have to distribute it to the other terms in that equation So the new bottom equation would look like this 4(-x - 3y =3) then distribute the 4 so -4x - 12y = 12. Once you cancel the x you can add the y and the answers from both equations. And find y from there.