Question

#Write a function called rabbit_hole. rabbit_hole should have#two parameters: a dictionary and a string. The string may be#a key to the dictionary. The value associated with that key,#in turn, may be another key to the dictionary.##Keep looking up the keys until you reach a key that has no#associated value. Then, return that key.##For example, imagine if you had the following dictionary.#This one is sorted to make this example easier to follow:## d = {"bat": "pig", "pig": "cat", "cat": "dog", "dog": "ant",# "cow": "bee", "bee": "elk", "elk": "fly", "ewe": "cod",# "cod": "hen", "hog": "fox", "fox": "jay", "jay": "doe",# "rat": "ram", "ram": "rat"}##If we called rabbit_hole(d, "bat"), then our code should...## - Look up "bat", and find "pig"# - Look up "pig", and find "cat"# - Look up "cat", and find "dog"# - Look up "dog", and find "ant"# - Look up "ant", and find no associated value, and so it would# return "ant".##Other possible results are:## rabbit_hole(d, "bat") -> "fly"# rabbit_hole(d, "ewe") -> "hen"# rabbit_hole(d, "jay") -> "doe"# rabbit_hole(d, "yak") -> "yak"##Notice that if the initial string passed in is not a key in#the dictionary, that string should be returned as the result as#well.##Note, however, that it is possible to get into a loop. In the#dictionary above, rabbit_hole(d, "rat") would infinitely go#around between "rat" and "ram". You should prevent this: if a#key is ever accessed more than once (meaning a loop has been#reached), return the boolean False.##Hint: If you try to access a value from a dictionary that does#not exist, a KeyError will be raised

Answer 1

The function 'rabbit_hole' recursively searches a dictionary for a chain of keys until it finds one without an associated value or detects a loop, returning 'False' in the latter scenario.

Step-by-step explanation:

The student is asking how to write a function called rabbit_hole that takes a dictionary and a string as parameters. The function will use the string to look up values in the dictionary recursively until it finds a key with no associated value or encounters a loop, at which point it should return False. To achieve this, one must use a loop to traverse the dictionary keys, while keeping track of already accessed keys to detect loops.

The core of this function involves using a while loop to continue looking up keys until a non-existent key is reached. To handle the case where the initial string is not a key in the dictionary, we check if the dictionary contains the string as a key; if not, the function will return the string as the final result. If a loop is detected (identified by a key being accessed more than once), the function will return False.

Answer 2

The code is given below in Python with appropriate comments

Step-by-step explanation:

def rabbit_hole(d,key): #function for the operation

keyAccess=key

while True: #while statement

if key in d.keys():

key=d[key]

if(key==keyAccess):

return False

else:

return key

d = {"bat": "pig", "pig": "cat", "cat": "dog", "dog": "ant",

"cow": "bee", "bee": "elk", "elk": "fly", "ewe": "cod",

"cod": "hen", "hog": "fox", "fox": "jay", "jay": "doe",

"rat": "ram", "ram": "rat"}

#printing the results

print(rabbit_hole(d, "bat"))

print(rabbit_hole(d, "ewe"))

print(rabbit_hole(d, "jay"))

print(rabbit_hole(d, "yak"))

print(rabbit_hole(d, "rat"))