Answer:
Total possible sequences of rolls is 20.
Explanation:
A standard six-sided die is rolled $5$ times.
It is given that you are told that among the rolls, there was one $4,$ one $5,$ and three $6$'s.
We need to find possible sequences of rolls could there have been.
Total numbers to arrange (i.e.,4,5,6,6,6)= 5
Repleted numbers (i.e., 6,6,6) = 3
![5P_5=(5!)/((5-5)!)=5* 4* 3* 2* 1=120](https://img.qammunity.org/2021/formulas/mathematics/high-school/ptl9625w611mzx7qxjv7rv7onzyqhsp1m7.png)
![3P_3=(3!)/((3-3)!)=3* 2* 1=6](https://img.qammunity.org/2021/formulas/mathematics/high-school/lt305strutxh3gcgscuaymd1wykun6q0d5.png)
Total possible ways are
![Total=(5P_5)/(3P_3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/w76n7prlehd4vza3jdu2vak5luptsg9jxy.png)
![Total=(120)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/le9wpsyjl8sdvzlleijjy5bfc13cijstmu.png)
![Total=20](https://img.qammunity.org/2021/formulas/mathematics/high-school/699t1skp146u30xgw8mccl82mqhnjt8kd7.png)
Therefore, the total possible sequences of rolls is 20.