Question

10. Two men, starting at the same point, walk in opposite directions for 8 meters, turn left and walk another 6 meters. What is the distance between them?

Answer 1

The distance between them is 20 meters.

Explanation:

Let origin be the starting point.

Consider first man,

He travels first 8 m and then left 6 m( consider he moves along positive x axis)

Displacement = 8i + 6 j

Consider second man,

He travels first 8 m and then left 6 m( consider he moves along negative x axis)

Displacement = -8i - 6 j

Displacement between them = 8i + 6 j - ( -8i - 6 j) = 16 i + 12 j

`\texttt{Magnitude = }√(16^2+12^2)=20m`

The distance between them is 20 meters.