Question

Calculate the percent yield when 500 grams of carbon dioxide react with an excess of water to produce 640 grams of carbonic acid. CO2 + H2O ---> H2CO3

Answer 1

The answer to your question is 90.8%

Step-by-step explanation:

Balanced Reaction

CO₂ + H₂O ⇒ H₂CO₃

Process

1.- Calculate the theoretical production of H₂CO₃

Molecular mass of CO₂ = 12 + 32 = 44 g

Molecular mass of H₂CO₃ = 2 + 12 + 48 = 62 g

44 g of CO₂ ---------------- 62 g of H₂CO₃

500 g of CO₂ --------------- x

x = (500 x 62) / 44

x = 704.54 moles of H₂CO₃

2.- Calculate the percent yield

Formula

`Percent yield = (experimental amount)/(theoretical amount) x 100`

Substitution

`Percent yield = (640)/(704.54) x 100`

Result = 90.8 %