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A friend of yours is loudly singing a single note at 403 Hz while racing toward you at 26.3 m/s on a day when the speed of sound is 340 m/s .What frequency do you hear?What frequency does your friend hear if you suddenly start singing at 403?

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Answer:

Step-by-step explanation:

Given

Natural frequency of vibration
f=403\ Hz

Velocity of source
v_s=26.3\ m/s

Considering velocity of sound
v=341\ m/s

Apparent Frequency of sound is given by Doppler effect


f'=(v+v_o)/(v-v_s)\cdot f

where
f=natural\ frequency


v=velocity\ of\ sound\ wave


v_o=velocity\ of\ observer


v_s=velocity\ of\ source


f'=apparent\ frequency

here
v_o=0


f'=(341)/(341-26.3)\cdot 403=437.37 Hz

If you start singing at frequency of 403 Hz then apparent frequency to your friend

Observer is moving with 26.3 m/s and source is stationary


f'=(v+26.3)/(v-0)\cdot 403


f'=(341+26.3)/(341)\cdot 403=434.08\ Hz

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