Question

A net force of 6.8 N accelerates a 31 kg scooter across a level parking lot. What is the magnitude of the scooter’s acceleration?a) 0.22 m/s2b) 0.69 m/s2c) 3.2 m/s2d) 4.6 m/s2

Answer 1

A

Step-by-step explanation:

It is

Answer 2

a)0.22 m/s².

Step-by-step explanation:

Given that

Net force ,F= 6.8 N

mass ,m = 31 kg

From the second law of Newton's

F = m a ---------------1

Where

F=Net force ,m=mass

a=Acceleration

Now by putting the values in the equation 1

F = m a

6.8 = 31 x a

`a=(6.8)/(31)\ m/s^2`

`a = 0.219\ m/s^2`

`a = 0.22\ m/s^2`

Therefore the acceleration of the scooter will be 0.22 m/s².

The answer will be "a".

a)0.22 m/s².