Question

A potter’s wheel of radius 17 cm starts from rest and rotates with constant angular acceleration until at the end of 32 s it is moving with angular velocity of 20 rad/s.

A) What is the angular acceleration?
B) What is the linear velocity of a point on the rim at the end of the 32 s?
C) What is the average angular velocity of the wheel during the 32 s?
D) Through what angle did the wheel rotate in the 32 s?

Answer 1

α=0.625rad/s^2

v=340m/s

w=10rad/s

θ=320rad

Step-by-step explanation:

Constant angular acceleration = ∆w/∆t

angular acceleration = 20/32

α=0.625rad/s^2

Linear velocity v=wr

v = 20×17= 340m/s

Average angular velocity

w0+w1/2

w= 0+20/2

w= 20/2

w=10rad/s

What angle did it rotate with

θ=wt

θ= 10×32

=320rad