Answer: C) 60
Explanation:
"At least 2" simply means 2 or more.
2 cities can be selected from 4 cities in 4C2 ways and these two cities, let's say A and B would have two distinct itineraries AB and BA.
Mathematically, that can be done either in 4C2*2! or 4P2 ways = 12.
Also, 3 cities in 4C3*3! or 4P3 ways = 24; that is, 4 cities in 4C4*4! or 4P4 ways = 24.
Total 12+24+24=60 ways.
The correct option is C