Answer:
Part a):
Number of letters = 10
Repeated letters: P=3 times , E = 2 times, R = 2 times
Given word can make strings = 10!/ 3! * 2! * 2! * 1! * 1! * 1!
Total Permutations = 3628800/24 = 151200
Part b):
Given word = AARDVARK
Taking A's as a single letter = AAA RDVRK
Number of strings we can make = 6! / 2! = 360
Part c):
Given that:
Total possible permutations = 26!
Let the permutation for fish = X, rat = Y, bird = Z
X = 23! , Y = 24! , Z = 23!
Now according to given scenario:
|X U Y U Z | = |X| + |Y| + |Z| − |X ∩ Y| − |X ∩ Z| − |Y ∩ Z| + |X∩ Y∩ Z |
As we know:
X intersection Y = Y intersection Z = X intersection Y intersection Z = phi
So, | X U Y U Z | = 24! + 2 · 23! − 21!.
=> 26! − 24! − 2 · 23! + 21!
is the required answer.
i hope it will help you!