Answer:
(1) Null Hypothesis,
:
<= 35 minutes
(2) Calculated value of the test statistic is 1.6
(3) We conclude that homework was actually more time consuming
Explanation:
We are given that the time spent by DCSI3710 students on trying to certify any HLS homework is known to have a mean of 35 minutes.
(1) Null Hypothesis,
:
<= 35 minutes {means that the homework takes less than or equal to 35 minutes}
Alternate Hypothesis,
:
> 35 minutes {means that the homework was actually more time consuming as it takes more than 35 minutes}
(2) We are provided that the sample of 16 students had a mean completion time of 39 minutes and the sample standard deviation was 10 minutes.
So, the test statistics used here will be;
T.S. =
~
where, X bar = sample mean = 39 minutes
s = sample standard deviation = 10 minutes
n = sample of students = 16
So, test statistics =
~
= 1.6
So, calculated value of the test statistic in this case is 1.6 .
(3) We are given that p-value associated with the test statistic is 0.08 or 8% . And the significance level is given as 0.1 or 10%.
It is stated that If p-value is less than significance level ⇒ Reject
If p-value is more than significance level ⇒ Do not Reject
Since here, p-value is less than the significance level as 8% < 10% so we conclude that null hypothesis must be rejected.
Therefore, we conclude that homework was actually more time consuming.