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The marks on a statistics test are normally distributed with a mean of 62 and a variance of 225. If the instructor wishes to assign Bs or higher to the top 25% of the students in the class, what mark is required to get a B or higher?

User Hsmiths
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1 Answer

2 votes

Answer:

79 marks are required to get a B or higher.

Explanation:

We have been given that the marks on a statistics test are normally distributed with a mean of 62 and a variance of 225. The instructor wishes to assign Bs or higher to the top 25% of the students in the class.

We will use normal distribution table and z-score formula to solve our given problem.


z=(x-\mu)/(\sigma), where,

z= Z-score,

x = Sample score,


\mu=\text{Mean}\\\sigma=\text{Standard deviation}

We know that standard deviation is equal to square-root of variance, so SD for given data would be
√(225)=15.


z=(x-62)/(25)

We know that top 25% means 75% and more.

Let us find z-score corresponding to 75% or 0.75 using normal distribution table.


0.68=(x-62)/(25)

Let us solve for x.


0.68*25=(x-62)/(25)*25


17=x-62


17+62=x-62+62


79=x

Therefore, 79 marks are required to get a B or higher.

User Naval Kishore
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