Question

Calculate the energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom.E = _____________ JoulesIs this an Absorption (A) or an Emission (E) process ?

Answer 1

The energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom is
`2.66* 10^(-20) Joule`.

Absorption is taking place.

Step-by-step explanation:

`E_n=-13.6* (Z^2)/(n^2)ev`

where,

`E_n` = energy of
`n^(th)` orbit

n = number of orbit

Z = atomic number

Energy of n = 5 in an hydrogen atom:

`E_5=-13.6* (1^2)/(5^2)eV=-0.544 eV`

Energy of n = 2 in an hydrogen atom:

`E_6=-13.6* (1^2)/(6^2)eV=-0.378 eV`

Energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom = E

`E=E_6-E_5=-0.378 eV-(-0.544 eV)=0.166 eV`

Positive value of energy means that absorption is taking place that electron excite from lower energy level to higher energy level by absorbing the energy.

`eV=1.60218 * 10^(-19) J`

`E=0.166 eV=0.166* 1.60218 * 10^(-19) J`

E =
`2.66* 10^(-20) Joule`

The energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom is
`2.66* 10^(-20) Joule`.