Question

A thin-walled hollow tube rolls without sliding along the floor. The ratio of its translational kinetic energy to its rotational kinetic energy (about an axis through its center of mass) is:

Answer 1

1

Step-by-step explanation:

took the test

Answer 2

Answer:1

Step-by-step explanation:

Thin-walled hollow tube is rolling without sliding on the floor

Moment of inertia of the hollow cylinder
`I=mr^2`

where m=mass of cylinder

r=radius of cylinder

Rotational Energy of cylinder
`=(1)/(2)I\omega^2`

In rolling
`\omega =(v)/(r)`

`R.K.E=(1)/(2)* mr^2* ((v)/(r))^2`

`R.K.E.=(1)/(2)mv^2`

Translational kinetic Energy of Cylinder is given by

`T.K.E.=(1)/(2)mv^2`

Ratio of translational kinetic energy to rotational Kinetic Energy

`=((1)/(2)mv^2)/((1)/(2)mv^2)`

`=1`