Question

Four different resistors have various amounts of electric current flowing through them.

Given the values of current I and resistance R in each case, order the resistors by the voltage across them, from highest to lowest. Highest voltage across Lowest voltage across.

-I=6.0 A, R= 4.0 Ω

-I=9.0 A, R= 2.0Ω

-l=3.0 A, R= 2.0 Ω

-I=8.0 A, R= 8.0 Ω

Answer 1

Order will be Forth resistor , first resistor, second resistor, third resistor

Step-by-step explanation:

We have given four different resistance and current flowing through them

In first resistor resistance R = 4 ohm and current flowing i = 6 A

According to ohm's law voltage = current × resistance = 6×4 = 24 volt

In second resistor resistance R = 2 ohm and current i = 9 A

So voltage V = 9×2 = 18 volt

In third resistor resistance R = 2 ohm and current i = 3 A

So voltage V = 3×2 = 6 volt

In forth resistor resistance R = 8 ohm and current i = 8 A

So voltage V = 8×8 = 64 volt

So order of highest voltage to lowest voltage is 64,24,18,6

Forth resistor , first resistor, second resistor, third resistor