Answer:
![P(x=7) = 1/3\\P(x=6) = 1/3\\P(X=3) = 1/3](https://img.qammunity.org/2021/formulas/mathematics/college/v31ugysamoreu069h1qqr50nufzxl9qikm.png)
Explanation:
Given that there are three cards in a deck: one marked with a 1, one marked with a 2, and one marked with a 5
You draw two cards at random and without replacement from the deck of three cards. The sample space S = {(1,2), (2,1),(1,5),(5,1),(2,5),(5,2)} consists of these six equally likely outcomes
X = total of two cards can take values as
X 3 6 7
P 1/3 1/3 1/3
i.e. probability distribution for sum is
![P(x=7) = 1/3\\P(x=6) = 1/3\\P(X=3) = 1/3](https://img.qammunity.org/2021/formulas/mathematics/college/v31ugysamoreu069h1qqr50nufzxl9qikm.png)