187k views
3 votes
Help ASAP lines a and b are perpendicular. The equation of like a is y=1/3x+3 what is the equation of line b

Help ASAP lines a and b are perpendicular. The equation of like a is y=1/3x+3 what-example-1
User Shezad
by
6.4k points

1 Answer

6 votes

Answer:

y = -3x - 4

Explanation:

From the graph we see that the equation of a line is y =
$  (1)/(3)x + 3 $

Note that the product of the slopes of perpendicular lines = -1.

The general equation of the line is: y = mx + c, where m is the slope.

Since the slope of this line is 1/3, the slope of its perpendicular line should be -3.

Therefore, we arrive at the slope - one point form to determine the equation of the line.

That is: (y - y₁) = m(x - x₁)

where, (x₁, y₁) is the point passing through the given line.

Here, from the graph the point (0, 4) passes through it.

So, y - (-4) = -3(x - 0)

⇒ y + 4 = -3x

y = -3x - 4 which is the required equation of the line.

User Guido Lodetti
by
6.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.