Question

A cross is carried out between two heterozygous individuals (AaBb) where the genes A and B are not linked genes. What would be the proportions of genotypic recombinants among the offspring of this cross? *

Answer 1

The proportion of the genotypic recombinants among the offspring from this cross is 75%

Step-by-step explanation:

Separating the alleles from the parents independently, We have AB, Ab, aB, and ab.

These should be crossed using punnet's square, we will therefore get the genotypic of the 16 progenies as: AABB, AABb, AaBB, AABb, AAbb, AaBb, AaBB, AaBb, aaBB, AaBb, Aabb, aaBb, aabb, aaBb, Aaaa and AaBb. From these, only those in bold retained the genotype of their heterozygous parents. Therefore, 12 out of 16 are genetic recombinant, which are the offspring that differs from their parents after a cross. This made the proportion to be 12/16 X 100 = 75%.