Answer:
correct option is (B) 315,500
Step-by-step explanation:
given data
volume = 320,000 yd³ = 8640000 ft³
dry unit weight = 106 pcf
moisture content = 18.2%
total unit weight = 122 pcf
moisture content = 16.7%
to find out
volume of borrow lyd needed
solution
first we get here weight of material that is
weight = volume × unit weight
weight = 8640000 × 122
weight = 1054080000 lb
that weight is weight of water + weight of solid so
0.167 × weight is weight of water + weight of solid ) = 1054080000 lb
and weight of solid =

weight of soil solid is = 903239075 pound
and weight of water = 150840925 pound
so volume of soil = 903239075 ÷ 106 lb/ft³ = 8521123.34 ft³
and volume required = 8521123.34 ft³ ÷ 27 ft³ = 315597.161 yd³
volume required = 315500 yd³
so correct option is (B) 315,500