Question

30 points - please help

Ion charges: (Na^+, Fe^3+, OH-, NO3-)
Write a balanced chemical equation for the change you observed in the laboratory
(4 points) Answer:
Note that the reaction in this experiment is;
Iron (III) nitrate + sodium hydroxide → iron (III) hydroxide + sodium nitrate
How many grams of sodium nitrate formed when 1.5 moles of iron (III) nitrate reacted with excess of sodium hydroxide? Note: use a periodic table, write units for your result and SHOW YOUR WORK ☺

Answer 1

Fe(NO₃)₃ + 3NaOH → Fe(OH)₃ + 3NaNO₃

382.5 grams of NaNO₃ are formed, initially from 1.5 moles of Fe(NO₃)₃

Step-by-step explanation:

This is the reaction:

Fe(NO₃)₃ + 3NaOH → Fe(OH)₃ + 3NaNO₃

Ratio is 1:3

So 1 mol of iron(III) nitrate is needed to produce 3 moles of sodium nitrate

1,5 moles of Fe(NO₃)₃ will produce (1.5 . 3) = 4.5 moles of NaNO₃

Molar mass of sodium nitrate: 85 g/m

Mol . molar mass = grams → 4.5 m . 85 g/m = 382.5 grams