Answer:
The linear function is
![y=50x+20](https://img.qammunity.org/2021/formulas/mathematics/middle-school/clhzrkxldbry3qlkpsletl5uyxnkf9mpmp.png)
The reasonable domain is
![0\ hours \leq x\leq 2\ hours](https://img.qammunity.org/2021/formulas/mathematics/middle-school/uqluvr3b64fo1zbfuqk4sjxd5hvox56qva.png)
Explanation:
Let
x ----> the time in hours
y ---> the distance in miles
we know that
The linear equation in slope intercept form is equal to
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
where
m is the slope or unit rate
b is the y-intercept or initial value
In this problem
The slope is
![m=50\ (miles)/(hour)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hgz8cv065y9qntjvhn8rcn9tj1ru24lqlw.png)
The y-intercept is
![b=20\ miles](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fvw71xnh3zr8szhu8s09opsvcal7bzlyy7.png)
substitute
![y=50x+20](https://img.qammunity.org/2021/formulas/mathematics/middle-school/clhzrkxldbry3qlkpsletl5uyxnkf9mpmp.png)
Find the domain for x
For y=120 miles
Find the value of x
substitute the value of y in the linear equation and solve for x
![120=50x+20](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qw3qblb6eezu9v6rlnqfs6lg36653rp59g.png)
![50x=120-20](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9s14b7znysml8xszvuvjfb1iq8iyy9nrzr.png)
![50x=100](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pmpo0lhgh8t3g1yaraafb3dyony1hrs47e.png)
![x=2\ hours](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kgc9jutdjmpnoc9ipsfkred9gqzyv1myd2.png)
therefore
The domain is the interval [0,2]
![0\ hours \leq x\leq 2\ hours](https://img.qammunity.org/2021/formulas/mathematics/middle-school/uqluvr3b64fo1zbfuqk4sjxd5hvox56qva.png)