Question

Find the equation of the line that is perpendicular to y =2/3

x − 5 and passes through (6, -1).

Answer 1

Explanation:

Hello:

the equation is : y = ax+b

the slope is a : a×(2/3) = -1......( perpendicular to a line with a slope of 2/3 because the equation y=2/3 x -5)

a = -3/2 y=(-3/2)x+b

the line that passes through (6, -1) : -1 = (-3/2)(6)+b

b = 0

the equation is : y = (-3/2)x