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If a square region with side x and a circular region with radius r have the same area, then x must be how many times as great as r?
A. 1π1π
B. 1π√1π
C. π√π
D. ππ
E. π2

User ZettaP
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1 Answer

3 votes

Answer:

C.
√(\pi)

Explanation:

We have been given that a square region with side x and a circular region with radius r have the same area. We are asked to find that x must be how many times as great as r.

We know that area of a square is square of its each side length, so area of square region with side x would be
x^2.

We also know that area of circle is
\pi r^2.

Since we have been given that both areas are same, so we will equate both areas as:


x^2=\pi r^2

Let us take positive square root of both sides as:


√(x^2)=√(\pi r^2)


x=√(\pi)\cdot √(r^2)


x=√(\pi)\cdot r

Let us divide both sides by r:


(x)/(r)=(√(\pi)\cdot r)/(r)


(x)/(r)=√(\pi)

Therefore, x must be
√(\pi) times greater than r and option C is the correct choice.

User Hidden
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