Answer:
The formula for the moose population is

Explanation:
In 1992—that is, 2 years after 1990 or at
—the population
is 3570, and in 1999 (
) population is 3640; so we have

Now the formula that will model the moose population will be of the form:

The slope
is

therefore we have

Now we know that at
, so we put these values in and solve for



With this value of
, we finally have the formula for the moose population:
